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a^2+10^2=25^2
We move all terms to the left:
a^2+10^2-(25^2)=0
We add all the numbers together, and all the variables
a^2-525=0
a = 1; b = 0; c = -525;
Δ = b2-4ac
Δ = 02-4·1·(-525)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{21}}{2*1}=\frac{0-10\sqrt{21}}{2} =-\frac{10\sqrt{21}}{2} =-5\sqrt{21} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{21}}{2*1}=\frac{0+10\sqrt{21}}{2} =\frac{10\sqrt{21}}{2} =5\sqrt{21} $
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